{"id":3164,"date":"2016-10-22T14:25:21","date_gmt":"2016-10-22T07:25:21","guid":{"rendered":"http:\/\/www.giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/"},"modified":"2016-10-22T14:25:21","modified_gmt":"2016-10-22T07:25:21","slug":"chemistry-thermodynamics-the-first-law","status":"publish","type":"post","link":"https:\/\/giasuquocte.edu.vn\/en\/chemistry-thermodynamics-the-first-law\/","title":{"rendered":"Chemistry &#8211; Thermodynamics &#8211; The First Law"},"content":{"rendered":"<div id=\"watu_quiz\" class=\"quiz-area single-page-quiz\">\n<form action=\"\" method=\"post\" class=\"quiz-form \" id=\"quiz-25\" >\n<div class='watu-question' id='question-1'><div class='question-content'><p><span class='watu_num'>1. <\/span><strong>For iodine, I2, at 114\u00b0C, the standard enthalpy of fusion is 16.1 kJ mol-1 and the standard enthalpy of vaporization is 45.0 kJ mol-1. Calculate the standard enthalpy of sublimation at this temperature.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='560' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2461' \/><div class='watu-question-choice'><input type='radio' name='answer-560[]' id='answer-id-2461' class='answer answer-1  answerof-560' value='2461' \/>&nbsp;<label for='answer-id-2461' id='answer-label-2461' class=' answer label-1'><span class='answer'> 61.1 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2464' \/><div class='watu-question-choice'><input type='radio' name='answer-560[]' id='answer-id-2464' class='answer answer-1  answerof-560' value='2464' \/>&nbsp;<label for='answer-id-2464' id='answer-label-2464' class=' answer label-1'><span class='answer'> 28.9 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2462' \/><div class='watu-question-choice'><input type='radio' name='answer-560[]' id='answer-id-2462' class='answer answer-1  answerof-560' value='2462' \/>&nbsp;<label for='answer-id-2462' id='answer-label-2462' class=' answer label-1'><span class='answer'> 16.1 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2463' \/><div class='watu-question-choice'><input type='radio' name='answer-560[]' id='answer-id-2463' class='answer answer-1  answerof-560' value='2463' \/>&nbsp;<label for='answer-id-2463' id='answer-label-2463' class=' answer label-1'><span class='answer'> 25.0 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType1' value='radio' class=''><\/div><div class='watu-question' id='question-2'><div class='question-content'><p><span class='watu_num'>2. <\/span><strong>Calculate the standard enthalpy change for the hydrogenation reaction. C2H4(g) + H2(g)\u2192C2H6(g) at 298.15 K. At this temperature, the standard enthalpy of combustion of ethene, C2H4, is -1409 kJ mol-1, of hydrogen, H2, is -286 kJ mol-1 and of ethane, C2H6 is -1560 kJ mol-1.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='567' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2492' \/><div class='watu-question-choice'><input type='radio' name='answer-567[]' id='answer-id-2492' class='answer answer-2  answerof-567' value='2492' \/>&nbsp;<label for='answer-id-2492' id='answer-label-2492' class=' answer label-2'><span class='answer'> -135 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2491' \/><div class='watu-question-choice'><input type='radio' name='answer-567[]' id='answer-id-2491' class='answer answer-2  answerof-567' value='2491' \/>&nbsp;<label for='answer-id-2491' id='answer-label-2491' class=' answer label-2'><span class='answer'> -3255 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2489' \/><div class='watu-question-choice'><input type='radio' name='answer-567[]' id='answer-id-2489' class='answer answer-2  answerof-567' value='2489' \/>&nbsp;<label for='answer-id-2489' id='answer-label-2489' class=' answer label-2'><span class='answer'> -151 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2490' \/><div class='watu-question-choice'><input type='radio' name='answer-567[]' id='answer-id-2490' class='answer answer-2  answerof-567' value='2490' \/>&nbsp;<label for='answer-id-2490' id='answer-label-2490' class=' answer label-2'><span class='answer'> -437 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType2' value='radio' class=''><\/div><div class='watu-question' id='question-3'><div class='question-content'><p><span class='watu_num'>3. <\/span><strong>Estimate the standard enthalpy change for the process. F2(g) + 2 e-(g) \u2192 2 F-(g) The F-F bond enthalpy is +155 kJ mol-1 and the electron gain enthalpy of elemental fluorine, F, is -328 kJ mol-1.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='563' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2473' \/><div class='watu-question-choice'><input type='radio' name='answer-563[]' id='answer-id-2473' class='answer answer-3  answerof-563' value='2473' \/>&nbsp;<label for='answer-id-2473' id='answer-label-2473' class=' answer label-3'><span class='answer'> -18 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2476' \/><div class='watu-question-choice'><input type='radio' name='answer-563[]' id='answer-id-2476' class='answer answer-3  answerof-563' value='2476' \/>&nbsp;<label for='answer-id-2476' id='answer-label-2476' class=' answer label-3'><span class='answer'> -811 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2474' \/><div class='watu-question-choice'><input type='radio' name='answer-563[]' id='answer-id-2474' class='answer answer-3  answerof-563' value='2474' \/>&nbsp;<label for='answer-id-2474' id='answer-label-2474' class=' answer label-3'><span class='answer'> -173 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2475' \/><div class='watu-question-choice'><input type='radio' name='answer-563[]' id='answer-id-2475' class='answer answer-3  answerof-563' value='2475' \/>&nbsp;<label for='answer-id-2475' id='answer-label-2475' class=' answer label-3'><span class='answer'> -501 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType3' value='radio' class=''><\/div><div class='watu-question' id='question-4'><div class='question-content'><p><span class='watu_num'>4. <\/span><strong>Calculate the standard enthalpy of combustion of phenol, C6H5OH, at 298.15 K given that, at this temperature, the standard enthalpy of formation of phenol is -165.0 kJ mol-1, of liquid water, H2O is -285.8 kJ mol-1 and gaseous carbon dioxide, CO2, is -393.51 kJ mol-1.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='562' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2472' \/><div class='watu-question-choice'><input type='radio' name='answer-562[]' id='answer-id-2472' class='answer answer-4  answerof-562' value='2472' \/>&nbsp;<label for='answer-id-2472' id='answer-label-2472' class=' answer label-4'><span class='answer'> -1872.9 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2471' \/><div class='watu-question-choice'><input type='radio' name='answer-562[]' id='answer-id-2471' class='answer answer-4  answerof-562' value='2471' \/>&nbsp;<label for='answer-id-2471' id='answer-label-2471' class=' answer label-4'><span class='answer'> -844.3 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2469' \/><div class='watu-question-choice'><input type='radio' name='answer-562[]' id='answer-id-2469' class='answer answer-4  answerof-562' value='2469' \/>&nbsp;<label for='answer-id-2469' id='answer-label-2469' class=' answer label-4'><span class='answer'> -2202.9 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2470' \/><div class='watu-question-choice'><input type='radio' name='answer-562[]' id='answer-id-2470' class='answer answer-4  answerof-562' value='2470' \/>&nbsp;<label for='answer-id-2470' id='answer-label-2470' class=' answer label-4'><span class='answer'> -514.3 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType4' value='radio' class=''><\/div><div class='watu-question' id='question-5'><div class='question-content'><p><span class='watu_num'>5. <\/span><strong>The standard enthalpy of combustion of propane, C3H8, is -2.220 \u00d7 103 kJ mol-1 at 400 K. Use the data below, and Kirchoff&#8217;s law, to calculate the standard enthalpy of combustion at 600 K.<\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-3181 alignleft\" src=\"http:\/\/www.giasuquocte.edu.vn\/wp-content\/uploads\/2016\/10\/20.0.jpg\" alt=\"20-0\" width=\"419\" height=\"81\" srcset=\"https:\/\/giasuquocte.edu.vn\/wp-content\/uploads\/2016\/10\/20.0.jpg 419w, https:\/\/giasuquocte.edu.vn\/wp-content\/uploads\/2016\/10\/20.0-300x58.jpg 300w\" sizes=\"auto, (max-width: 419px) 100vw, 419px\" \/><\/p>\n<\/div><input type='hidden' name='question_id[]' value='568' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2494' \/><div class='watu-question-choice'><input type='radio' name='answer-568[]' id='answer-id-2494' class='answer answer-5  answerof-568' value='2494' \/>&nbsp;<label for='answer-id-2494' id='answer-label-2494' class=' answer label-5'><span class='answer'> -445 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2495' \/><div class='watu-question-choice'><input type='radio' name='answer-568[]' id='answer-id-2495' class='answer answer-5  answerof-568' value='2495' \/>&nbsp;<label for='answer-id-2495' id='answer-label-2495' class=' answer label-5'><span class='answer'> -2195 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2493' \/><div class='watu-question-choice'><input type='radio' name='answer-568[]' id='answer-id-2493' class='answer answer-5  answerof-568' value='2493' \/>&nbsp;<label for='answer-id-2493' id='answer-label-2493' class=' answer label-5'><span class='answer'> -2205 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2496' \/><div class='watu-question-choice'><input type='radio' name='answer-568[]' id='answer-id-2496' class='answer answer-5  answerof-568' value='2496' \/>&nbsp;<label for='answer-id-2496' id='answer-label-2496' class=' answer label-5'><span class='answer'> -2129 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType5' value='radio' class=''><\/div><div class='watu-question' id='question-6'><div class='question-content'><p><span class='watu_num'>6. <\/span><strong>The temperature of a copper block of mass 423 g rises by 10.1\u00b0C. Calculate the heat transferred, given that the specific heat capacity of copper is 385 J K-1 kg-1.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='551' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2425' \/><div class='watu-question-choice'><input type='radio' name='answer-551[]' id='answer-id-2425' class='answer answer-6  answerof-551' value='2425' \/>&nbsp;<label for='answer-id-2425' id='answer-label-2425' class=' answer label-6'><span class='answer'> 385 J<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2427' \/><div class='watu-question-choice'><input type='radio' name='answer-551[]' id='answer-id-2427' class='answer answer-6  answerof-551' value='2427' \/>&nbsp;<label for='answer-id-2427' id='answer-label-2427' class=' answer label-6'><span class='answer'> 1.10 kJ<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2426' \/><div class='watu-question-choice'><input type='radio' name='answer-551[]' id='answer-id-2426' class='answer answer-6  answerof-551' value='2426' \/>&nbsp;<label for='answer-id-2426' id='answer-label-2426' class=' answer label-6'><span class='answer'> 1.63 kJ<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2428' \/><div class='watu-question-choice'><input type='radio' name='answer-551[]' id='answer-id-2428' class='answer answer-6  answerof-551' value='2428' \/>&nbsp;<label for='answer-id-2428' id='answer-label-2428' class=' answer label-6'><span class='answer'> 25.6 kJ<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType6' value='radio' class=''><\/div><div class='watu-question' id='question-7'><div class='question-content'><p><span class='watu_num'>7. <\/span><strong>The molar heat capacity at constant volume of argon, Ar, is 12.47 J K mol-1. What is the value of the molar heat capacity at constant pressure?<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='558' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2453' \/><div class='watu-question-choice'><input type='radio' name='answer-558[]' id='answer-id-2453' class='answer answer-7  answerof-558' value='2453' \/>&nbsp;<label for='answer-id-2453' id='answer-label-2453' class=' answer label-7'><span class='answer'> 4.15 J K-1 mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2454' \/><div class='watu-question-choice'><input type='radio' name='answer-558[]' id='answer-id-2454' class='answer answer-7  answerof-558' value='2454' \/>&nbsp;<label for='answer-id-2454' id='answer-label-2454' class=' answer label-7'><span class='answer'> 8.31 J K-1 mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2455' \/><div class='watu-question-choice'><input type='radio' name='answer-558[]' id='answer-id-2455' class='answer answer-7  answerof-558' value='2455' \/>&nbsp;<label for='answer-id-2455' id='answer-label-2455' class=' answer label-7'><span class='answer'> 12.47 J K-1 mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2456' \/><div class='watu-question-choice'><input type='radio' name='answer-558[]' id='answer-id-2456' class='answer answer-7  answerof-558' value='2456' \/>&nbsp;<label for='answer-id-2456' id='answer-label-2456' class=' answer label-7'><span class='answer'> 20.78 J K-1 mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType7' value='radio' class=''><\/div><div class='watu-question' id='question-8'><div class='question-content'><p><span class='watu_num'>8. <\/span><strong>In an experiment to determine its enthalpy of vaporization, liquid tetrachloromethane, CCl4, was placed in an open boiler that was equipped with a resistive heating coil and brought to the boil at a constant temperature of 350 K and pressure of 1 bar. The passage of a current of 0.933 A from a 24.0 V supply for 30.0 s was found to result in the vaporization of 3.45 g of tetrachloromethane. Calculate the standard enthalpy of vaporization of tetrachloromethane at 350 K.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='559' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2457' \/><div class='watu-question-choice'><input type='radio' name='answer-559[]' id='answer-id-2457' class='answer answer-8  answerof-559' value='2457' \/>&nbsp;<label for='answer-id-2457' id='answer-label-2457' class=' answer label-8'><span class='answer'> 0.671 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2458' \/><div class='watu-question-choice'><input type='radio' name='answer-559[]' id='answer-id-2458' class='answer answer-8  answerof-559' value='2458' \/>&nbsp;<label for='answer-id-2458' id='answer-label-2458' class=' answer label-8'><span class='answer'> 30.0 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2460' \/><div class='watu-question-choice'><input type='radio' name='answer-559[]' id='answer-id-2460' class='answer answer-8  answerof-559' value='2460' \/>&nbsp;<label for='answer-id-2460' id='answer-label-2460' class=' answer label-8'><span class='answer'> 2.32 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2459' \/><div class='watu-question-choice'><input type='radio' name='answer-559[]' id='answer-id-2459' class='answer answer-8  answerof-559' value='2459' \/>&nbsp;<label for='answer-id-2459' id='answer-label-2459' class=' answer label-8'><span class='answer'> 195 J mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType8' value='radio' class=''><\/div><div class='watu-question' id='question-9'><div class='question-content'><p><span class='watu_num'>9. <\/span><strong>The energy released as heat when liquid propanone, CH3COCH3, is burned in a bomb calorimeter at 298.15 K is 1788 kJ mol-1. Calculate the enthalpy of combustion of propanone.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='561' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2467' \/><div class='watu-question-choice'><input type='radio' name='answer-561[]' id='answer-id-2467' class='answer answer-9  answerof-561' value='2467' \/>&nbsp;<label for='answer-id-2467' id='answer-label-2467' class=' answer label-9'><span class='answer'> -1790 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2465' \/><div class='watu-question-choice'><input type='radio' name='answer-561[]' id='answer-id-2465' class='answer answer-9  answerof-561' value='2465' \/>&nbsp;<label for='answer-id-2465' id='answer-label-2465' class=' answer label-9'><span class='answer'> +1790 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2466' \/><div class='watu-question-choice'><input type='radio' name='answer-561[]' id='answer-id-2466' class='answer answer-9  answerof-561' value='2466' \/>&nbsp;<label for='answer-id-2466' id='answer-label-2466' class=' answer label-9'><span class='answer'> +1786 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2468' \/><div class='watu-question-choice'><input type='radio' name='answer-561[]' id='answer-id-2468' class='answer answer-9  answerof-561' value='2468' \/>&nbsp;<label for='answer-id-2468' id='answer-label-2468' class=' answer label-9'><span class='answer'> -1786 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType9' value='radio' class=''><\/div><div class='watu-question' id='question-10'><div class='question-content'><p><span class='watu_num'>10. <\/span><strong>Calculate the difference between the molar internal energy and the molar enthalpy for a perfect gas at 298.15 K.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='556' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2445' \/><div class='watu-question-choice'><input type='radio' name='answer-556[]' id='answer-id-2445' class='answer answer-10  answerof-556' value='2445' \/>&nbsp;<label for='answer-id-2445' id='answer-label-2445' class=' answer label-10'><span class='answer'> 35.859 J mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2446' \/><div class='watu-question-choice'><input type='radio' name='answer-556[]' id='answer-id-2446' class='answer answer-10  answerof-556' value='2446' \/>&nbsp;<label for='answer-id-2446' id='answer-label-2446' class=' answer label-10'><span class='answer'> 0 J mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2448' \/><div class='watu-question-choice'><input type='radio' name='answer-556[]' id='answer-id-2448' class='answer answer-10  answerof-556' value='2448' \/>&nbsp;<label for='answer-id-2448' id='answer-label-2448' class=' answer label-10'><span class='answer'> 8.3145 J mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2447' \/><div class='watu-question-choice'><input type='radio' name='answer-556[]' id='answer-id-2447' class='answer answer-10  answerof-556' value='2447' \/>&nbsp;<label for='answer-id-2447' id='answer-label-2447' class=' answer label-10'><span class='answer'> 2.4790 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType10' value='radio' class=''><\/div><div class='watu-question' id='question-11'><div class='question-content'><p><span class='watu_num'>11. <\/span><strong>1.00 mol of gas in a cylinder is compressed reversibly by increasing the pressure from 1.00 bar to 10.0 bar at a constant temperature of 500 K. Calculate the work done on the gas by the compression.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='550' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2422' \/><div class='watu-question-choice'><input type='radio' name='answer-550[]' id='answer-id-2422' class='answer answer-11  answerof-550' value='2422' \/>&nbsp;<label for='answer-id-2422' id='answer-label-2422' class=' answer label-11'><span class='answer'> +3740 J<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2421' \/><div class='watu-question-choice'><input type='radio' name='answer-550[]' id='answer-id-2421' class='answer answer-11  answerof-550' value='2421' \/>&nbsp;<label for='answer-id-2421' id='answer-label-2421' class=' answer label-11'><span class='answer'> +9570 J<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2424' \/><div class='watu-question-choice'><input type='radio' name='answer-550[]' id='answer-id-2424' class='answer answer-11  answerof-550' value='2424' \/>&nbsp;<label for='answer-id-2424' id='answer-label-2424' class=' answer label-11'><span class='answer'> +5710 J<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2423' \/><div class='watu-question-choice'><input type='radio' name='answer-550[]' id='answer-id-2423' class='answer answer-11  answerof-550' value='2423' \/>&nbsp;<label for='answer-id-2423' id='answer-label-2423' class=' answer label-11'><span class='answer'> +37.4 kJ<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType11' value='radio' class=''><\/div><div class='watu-question' id='question-12'><div class='question-content'><p><span class='watu_num'>12. <\/span><strong>Calculate the work done on the system when 1.00 mol of gas held behind a piston expands irreversibly from a volume of 1.00 dm3 to a volume of 10.0 dm3 against an external pressure of 1.00 bar.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='549' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2419' \/><div class='watu-question-choice'><input type='radio' name='answer-549[]' id='answer-id-2419' class='answer answer-12  answerof-549' value='2419' \/>&nbsp;<label for='answer-id-2419' id='answer-label-2419' class=' answer label-12'><span class='answer'> +1000 J<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2420' \/><div class='watu-question-choice'><input type='radio' name='answer-549[]' id='answer-id-2420' class='answer answer-12  answerof-549' value='2420' \/>&nbsp;<label for='answer-id-2420' id='answer-label-2420' class=' answer label-12'><span class='answer'> +9120 J<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2418' \/><div class='watu-question-choice'><input type='radio' name='answer-549[]' id='answer-id-2418' class='answer answer-12  answerof-549' value='2418' \/>&nbsp;<label for='answer-id-2418' id='answer-label-2418' class=' answer label-12'><span class='answer'> -900 J<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2417' \/><div class='watu-question-choice'><input type='radio' name='answer-549[]' id='answer-id-2417' class='answer answer-12  answerof-549' value='2417' \/>&nbsp;<label for='answer-id-2417' id='answer-label-2417' class=' answer label-12'><span class='answer'> -5710 J<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType12' value='radio' class=''><\/div><div class='watu-question' id='question-13'><div class='question-content'><p><span class='watu_num'>13. <\/span><strong>Estimate the standard enthalpy change for the reaction. N2(g) + 3 H2(g) \u2192 2 NH3(g) given the following mean bond enthalpies: H-H: +436 kJ mol-1, N-N: 945 kJ mol-1 and H-N: 388 kJ mol-1.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='564' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2478' \/><div class='watu-question-choice'><input type='radio' name='answer-564[]' id='answer-id-2478' class='answer answer-13  answerof-564' value='2478' \/>&nbsp;<label for='answer-id-2478' id='answer-label-2478' class=' answer label-13'><span class='answer'> -75 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2479' \/><div class='watu-question-choice'><input type='radio' name='answer-564[]' id='answer-id-2479' class='answer answer-13  answerof-564' value='2479' \/>&nbsp;<label for='answer-id-2479' id='answer-label-2479' class=' answer label-13'><span class='answer'> -2690 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2480' \/><div class='watu-question-choice'><input type='radio' name='answer-564[]' id='answer-id-2480' class='answer answer-13  answerof-564' value='2480' \/>&nbsp;<label for='answer-id-2480' id='answer-label-2480' class=' answer label-13'><span class='answer'> +605 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2477' \/><div class='watu-question-choice'><input type='radio' name='answer-564[]' id='answer-id-2477' class='answer answer-13  answerof-564' value='2477' \/>&nbsp;<label for='answer-id-2477' id='answer-label-2477' class=' answer label-13'><span class='answer'> +933 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType13' value='radio' class=''><\/div><div class='watu-question' id='question-14'><div class='question-content'><p><span class='watu_num'>14. <\/span><strong>Raising the temperature of 1.00 dm3 of water from a temperature of 25\u00b0C to 100\u00b0C at constant pressure requires 312 kJ of heat. Calculate the molar heat capacity of water at constant pressure.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='552' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2430' \/><div class='watu-question-choice'><input type='radio' name='answer-552[]' id='answer-id-2430' class='answer answer-14  answerof-552' value='2430' \/>&nbsp;<label for='answer-id-2430' id='answer-label-2430' class=' answer label-14'><span class='answer'> 5.62 J K-1 mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2429' \/><div class='watu-question-choice'><input type='radio' name='answer-552[]' id='answer-id-2429' class='answer answer-14  answerof-552' value='2429' \/>&nbsp;<label for='answer-id-2429' id='answer-label-2429' class=' answer label-14'><span class='answer'> 4.16 J K-1 mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2432' \/><div class='watu-question-choice'><input type='radio' name='answer-552[]' id='answer-id-2432' class='answer answer-14  answerof-552' value='2432' \/>&nbsp;<label for='answer-id-2432' id='answer-label-2432' class=' answer label-14'><span class='answer'> 422 J K-1 mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2431' \/><div class='watu-question-choice'><input type='radio' name='answer-552[]' id='answer-id-2431' class='answer answer-14  answerof-552' value='2431' \/>&nbsp;<label for='answer-id-2431' id='answer-label-2431' class=' answer label-14'><span class='answer'> 75 J K-1 mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType14' value='radio' class=''><\/div><div class='watu-question' id='question-15'><div class='question-content'><p><span class='watu_num'>15. <\/span><strong>A calorimeter was calibrated by passing an electrical current through a heater and measuring the rise in temperature that resulted. When a current of 113 mA from a 24.1 V source was passed through the heater for 254 s, the temperature of the calorimeter rose by 2.61 \u00b0C. Determine the heat capacity of the calorimeter.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='553' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2436' \/><div class='watu-question-choice'><input type='radio' name='answer-553[]' id='answer-id-2436' class='answer answer-15  answerof-553' value='2436' \/>&nbsp;<label for='answer-id-2436' id='answer-label-2436' class=' answer label-15'><span class='answer'> 265 J K-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2435' \/><div class='watu-question-choice'><input type='radio' name='answer-553[]' id='answer-id-2435' class='answer answer-15  answerof-553' value='2435' \/>&nbsp;<label for='answer-id-2435' id='answer-label-2435' class=' answer label-15'><span class='answer'> 692 J K-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2434' \/><div class='watu-question-choice'><input type='radio' name='answer-553[]' id='answer-id-2434' class='answer answer-15  answerof-553' value='2434' \/>&nbsp;<label for='answer-id-2434' id='answer-label-2434' class=' answer label-15'><span class='answer'> 4.42 J K-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2433' \/><div class='watu-question-choice'><input type='radio' name='answer-553[]' id='answer-id-2433' class='answer answer-15  answerof-553' value='2433' \/>&nbsp;<label for='answer-id-2433' id='answer-label-2433' class=' answer label-15'><span class='answer'> 1.04 J K-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType15' value='radio' class=''><\/div><div class='watu-question' id='question-16'><div class='question-content'><p><span class='watu_num'>16. <\/span><strong>Estimate the standard enthalpy of formation of liquid benzene, C6H6, at 298.15 K. At this temperature, the standard enthalpy of atomization of carbon. C(s, graphite) \u2192 C(g) is +717 kJ mol-1 and the standard enthalpy of vaporization of benzene is 34 kJ mol-1, whilst the standard bond enthalpy of hydrogen, H2, is 436 kJ mol-1. The mean bond enthalpy of a C6H5-H bond is 469 kJ mol-1 and of an aromatic C-C bond is 452 kJ mol-1.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='565' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2481' \/><div class='watu-question-choice'><input type='radio' name='answer-565[]' id='answer-id-2481' class='answer answer-16  answerof-565' value='2481' \/>&nbsp;<label for='answer-id-2481' id='answer-label-2481' class=' answer label-16'><span class='answer'> +198 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2484' \/><div class='watu-question-choice'><input type='radio' name='answer-565[]' id='answer-id-2484' class='answer answer-16  answerof-565' value='2484' \/>&nbsp;<label for='answer-id-2484' id='answer-label-2484' class=' answer label-16'><span class='answer'> +50 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2483' \/><div class='watu-question-choice'><input type='radio' name='answer-565[]' id='answer-id-2483' class='answer answer-16  answerof-565' value='2483' \/>&nbsp;<label for='answer-id-2483' id='answer-label-2483' class=' answer label-16'><span class='answer'> +2310 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2482' \/><div class='watu-question-choice'><input type='radio' name='answer-565[]' id='answer-id-2482' class='answer answer-16  answerof-565' value='2482' \/>&nbsp;<label for='answer-id-2482' id='answer-label-2482' class=' answer label-16'><span class='answer'> +1102 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType16' value='radio' class=''><\/div><div class='watu-question' id='question-17'><div class='question-content'><p><span class='watu_num'>17. <\/span><strong>Which of the following statements is always true for a reaction in which there is no non-expansion work?<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='555' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2442' \/><div class='watu-question-choice'><input type='radio' name='answer-555[]' id='answer-id-2442' class='answer answer-17  answerof-555' value='2442' \/>&nbsp;<label for='answer-id-2442' id='answer-label-2442' class=' answer label-17'><span class='answer'> \u0394H = qp<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2443' \/><div class='watu-question-choice'><input type='radio' name='answer-555[]' id='answer-id-2443' class='answer answer-17  answerof-555' value='2443' \/>&nbsp;<label for='answer-id-2443' id='answer-label-2443' class=' answer label-17'><span class='answer'> \u0394U = 0<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2444' \/><div class='watu-question-choice'><input type='radio' name='answer-555[]' id='answer-id-2444' class='answer answer-17  answerof-555' value='2444' \/>&nbsp;<label for='answer-id-2444' id='answer-label-2444' class=' answer label-17'><span class='answer'> \u0394H = 0<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2441' \/><div class='watu-question-choice'><input type='radio' name='answer-555[]' id='answer-id-2441' class='answer answer-17  answerof-555' value='2441' \/>&nbsp;<label for='answer-id-2441' id='answer-label-2441' class=' answer label-17'><span class='answer'> \u0394U = qp<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType17' value='radio' class=''><\/div><div class='watu-question' id='question-18'><div class='question-content'><p><span class='watu_num'>18. <\/span><strong>A perfect gas expands reversibly at a constant temperature of 298 K so that its volume doubles. What is the change in the molar internal energy of the gas?<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='554' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2438' \/><div class='watu-question-choice'><input type='radio' name='answer-554[]' id='answer-id-2438' class='answer answer-18  answerof-554' value='2438' \/>&nbsp;<label for='answer-id-2438' id='answer-label-2438' class=' answer label-18'><span class='answer'> 0 J mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2439' \/><div class='watu-question-choice'><input type='radio' name='answer-554[]' id='answer-id-2439' class='answer answer-18  answerof-554' value='2439' \/>&nbsp;<label for='answer-id-2439' id='answer-label-2439' class=' answer label-18'><span class='answer'> +1.72 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2437' \/><div class='watu-question-choice'><input type='radio' name='answer-554[]' id='answer-id-2437' class='answer answer-18  answerof-554' value='2437' \/>&nbsp;<label for='answer-id-2437' id='answer-label-2437' class=' answer label-18'><span class='answer'> +2.27 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2440' \/><div class='watu-question-choice'><input type='radio' name='answer-554[]' id='answer-id-2440' class='answer answer-18  answerof-554' value='2440' \/>&nbsp;<label for='answer-id-2440' id='answer-label-2440' class=' answer label-18'><span class='answer'> -2.27 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType18' value='radio' class=''><\/div><div class='watu-question' id='question-19'><div class='question-content'><p><span class='watu_num'>19. <\/span><strong>For many substances, the variation with temperature of the molar heat capacity at constant pressure of is given by the expression. For copper, a = 22.64 J K-1 mol-1, b = 6.28 \u00d7 10-3 J K-2 mol-1 with the value of c being negligible. Estimate the change in the molar enthalpy of copper when it is heated from 293 to 323 K.<\/strong><\/p>\n<\/div><input type='hidden' name='question_id[]' value='557' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2450' \/><div class='watu-question-choice'><input type='radio' name='answer-557[]' id='answer-id-2450' class='answer answer-19  answerof-557' value='2450' \/>&nbsp;<label for='answer-id-2450' id='answer-label-2450' class=' answer label-19'><span class='answer'> +1.23 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2451' \/><div class='watu-question-choice'><input type='radio' name='answer-557[]' id='answer-id-2451' class='answer answer-19  answerof-557' value='2451' \/>&nbsp;<label for='answer-id-2451' id='answer-label-2451' class=' answer label-19'><span class='answer'> +737 J mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2449' \/><div class='watu-question-choice'><input type='radio' name='answer-557[]' id='answer-id-2449' class='answer answer-19  answerof-557' value='2449' \/>&nbsp;<label for='answer-id-2449' id='answer-label-2449' class=' answer label-19'><span class='answer'> +29.7 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2452' \/><div class='watu-question-choice'><input type='radio' name='answer-557[]' id='answer-id-2452' class='answer answer-19  answerof-557' value='2452' \/>&nbsp;<label for='answer-id-2452' id='answer-label-2452' class=' answer label-19'><span class='answer'> +1.13 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType19' value='radio' class=''><\/div><div class='watu-question' id='question-20'><div class='question-content'><p><span class='watu_num'>20. <\/span><strong>Use the following data to calculate the mean B-Cl bond enthalpy in boron trichloride, BCl3.<\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-3180 alignleft\" src=\"http:\/\/www.giasuquocte.edu.vn\/wp-content\/uploads\/2016\/10\/18.0.jpg\" alt=\"18-0\" width=\"418\" height=\"131\" srcset=\"https:\/\/giasuquocte.edu.vn\/wp-content\/uploads\/2016\/10\/18.0.jpg 418w, https:\/\/giasuquocte.edu.vn\/wp-content\/uploads\/2016\/10\/18.0-300x94.jpg 300w\" sizes=\"auto, (max-width: 418px) 100vw, 418px\" \/><\/p>\n<p>&nbsp;<\/p>\n<\/div><input type='hidden' name='question_id[]' value='566' \/><div class='watu-questions-wrap '><input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2486' \/><div class='watu-question-choice'><input type='radio' name='answer-566[]' id='answer-id-2486' class='answer answer-20  answerof-566' value='2486' \/>&nbsp;<label for='answer-id-2486' id='answer-label-2486' class=' answer label-20'><span class='answer'> +1371 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2487' \/><div class='watu-question-choice'><input type='radio' name='answer-566[]' id='answer-id-2487' class='answer answer-20  answerof-566' value='2487' \/>&nbsp;<label for='answer-id-2487' id='answer-label-2487' class=' answer label-20'><span class='answer'> +325 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2485' \/><div class='watu-question-choice'><input type='radio' name='answer-566[]' id='answer-id-2485' class='answer answer-20  answerof-566' value='2485' \/>&nbsp;<label for='answer-id-2485' id='answer-label-2485' class=' answer label-20'><span class='answer'> +975 kJ mol-1<\/span><\/label><\/div>\n<input type='hidden' name='answer_ids[]' class='watu-answer-ids' value='2488' \/><div class='watu-question-choice'><input type='radio' name='answer-566[]' id='answer-id-2488' class='answer answer-20  answerof-566' value='2488' \/>&nbsp;<label for='answer-id-2488' id='answer-label-2488' class=' answer label-20'><span class='answer'> +457 kJ mol-1<\/span><\/label><\/div>\n<\/div><input type='hidden' id='questionType20' value='radio' class=''><\/div><div style='display:none' id='question-21'><br \/><div class='question-content'><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/giasuquocte.edu.vn\/wp-content\/plugins\/watu\/loading.gif\" width=\"16\" height=\"16\" alt=\"Loading ...\" title=\"Loading ...\" \/>&nbsp;Loading &#8230;<\/div><\/div><br \/>\n<input type=\"button\" name=\"action\" onclick=\"Watu.submitResult()\" id=\"action-button\" value=\"Submit\"  class=\"watu-submit-button\" \/>\n<input type=\"hidden\" name=\"no_ajax\" value=\"0\"><input type=\"hidden\" name=\"quiz_id\" value=\"25\" \/>\n<input type=\"hidden\" id=\"watuStartTime\" name=\"start_time\" value=\"2026-05-23 20:30:58\" \/>\n<\/form>\n<\/div>\n<div id=\"watu-loading-result\" style=\"display:none;\">\n\t<p align=\"center\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/giasuquocte.edu.vn\/wp-content\/plugins\/watu\/loading.gif\" width=\"16\" height=\"16\" alt=\"Loading\" title=\"Loading\" \/><\/p>\n<\/div>\t\n<script type=\"text\/javascript\">\nvar exam_id=0;\nvar question_ids='';\nvar watuURL='';\njQuery(function($){\nquestion_ids = \"560,567,563,562,568,551,558,559,561,556,550,549,564,552,553,565,555,554,557,566\";\nexam_id = 25;\nWatu.exam_id = exam_id;\nWatu.qArr = question_ids.split(',');\nWatu.post_id = 3164;\nWatu.singlePage = '1';\nWatu.hAppID = \"0.21115800 1779543058\";\nwatuURL = \"https:\/\/giasuquocte.edu.vn\/wp-admin\/admin-ajax.php\";\nWatu.noAlertUnanswered = 1;\n});\n<\/script>\n","protected":false},"excerpt":{"rendered":"Please go to Chemistry &#8211; Thermodynamics &#8211; The First Law to view the test","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-3164","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v18.4.1 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Chemistry - Thermodynamics - The First Law - iTutor<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Chemistry - Thermodynamics - The First Law - iTutor\" \/>\n<meta property=\"og:url\" content=\"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/\" \/>\n<meta property=\"og:site_name\" content=\"iTutor\" \/>\n<meta property=\"article:published_time\" content=\"2016-10-22T07:25:21+00:00\" \/>\n<meta name=\"twitter:card\" content=\"summary\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Gia s\u01b0 Qu\u1ed1c t\u1ebf\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebSite\",\"@id\":\"https:\/\/giasuquocte.edu.vn\/#website\",\"url\":\"https:\/\/giasuquocte.edu.vn\/\",\"name\":\"iTutor\",\"description\":\"Gia S\u01b0 Ch\u01b0\u01a1ng Tr\u00ecnh Qu\u1ed1c T\u1ebf\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/giasuquocte.edu.vn\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/#webpage\",\"url\":\"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/\",\"name\":\"Chemistry - Thermodynamics - The First Law - iTutor\",\"isPartOf\":{\"@id\":\"https:\/\/giasuquocte.edu.vn\/#website\"},\"datePublished\":\"2016-10-22T07:25:21+00:00\",\"dateModified\":\"2016-10-22T07:25:21+00:00\",\"author\":{\"@id\":\"https:\/\/giasuquocte.edu.vn\/#\/schema\/person\/98c111e82c8b8bd46dd2aa462cb6a4c0\"},\"breadcrumb\":{\"@id\":\"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Trang ch\u1ee7\",\"item\":\"https:\/\/giasuquocte.edu.vn\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Chemistry &#8211; Thermodynamics &#8211; The First Law\"}]},{\"@type\":\"Person\",\"@id\":\"https:\/\/giasuquocte.edu.vn\/#\/schema\/person\/98c111e82c8b8bd46dd2aa462cb6a4c0\",\"name\":\"Gia s\u01b0 Qu\u1ed1c t\u1ebf\",\"image\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/giasuquocte.edu.vn\/#personlogo\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/00cdc2b0d235aa2573663adee2c1b6951ce936f219d875cdc61fd04f9ee46a35?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/00cdc2b0d235aa2573663adee2c1b6951ce936f219d875cdc61fd04f9ee46a35?s=96&d=mm&r=g\",\"caption\":\"Gia s\u01b0 Qu\u1ed1c t\u1ebf\"},\"url\":\"https:\/\/giasuquocte.edu.vn\/en\/author\/gsqt_ad\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Chemistry - Thermodynamics - The First Law - iTutor","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/","og_locale":"en_US","og_type":"article","og_title":"Chemistry - Thermodynamics - The First Law - iTutor","og_url":"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/","og_site_name":"iTutor","article_published_time":"2016-10-22T07:25:21+00:00","twitter_card":"summary","twitter_misc":{"Written by":"Gia s\u01b0 Qu\u1ed1c t\u1ebf"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebSite","@id":"https:\/\/giasuquocte.edu.vn\/#website","url":"https:\/\/giasuquocte.edu.vn\/","name":"iTutor","description":"Gia S\u01b0 Ch\u01b0\u01a1ng Tr\u00ecnh Qu\u1ed1c T\u1ebf","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/giasuquocte.edu.vn\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"WebPage","@id":"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/#webpage","url":"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/","name":"Chemistry - Thermodynamics - The First Law - iTutor","isPartOf":{"@id":"https:\/\/giasuquocte.edu.vn\/#website"},"datePublished":"2016-10-22T07:25:21+00:00","dateModified":"2016-10-22T07:25:21+00:00","author":{"@id":"https:\/\/giasuquocte.edu.vn\/#\/schema\/person\/98c111e82c8b8bd46dd2aa462cb6a4c0"},"breadcrumb":{"@id":"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/giasuquocte.edu.vn\/chemistry-thermodynamics-the-first-law\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Trang ch\u1ee7","item":"https:\/\/giasuquocte.edu.vn\/"},{"@type":"ListItem","position":2,"name":"Chemistry &#8211; Thermodynamics &#8211; The First Law"}]},{"@type":"Person","@id":"https:\/\/giasuquocte.edu.vn\/#\/schema\/person\/98c111e82c8b8bd46dd2aa462cb6a4c0","name":"Gia s\u01b0 Qu\u1ed1c t\u1ebf","image":{"@type":"ImageObject","@id":"https:\/\/giasuquocte.edu.vn\/#personlogo","inLanguage":"en-US","url":"https:\/\/secure.gravatar.com\/avatar\/00cdc2b0d235aa2573663adee2c1b6951ce936f219d875cdc61fd04f9ee46a35?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/00cdc2b0d235aa2573663adee2c1b6951ce936f219d875cdc61fd04f9ee46a35?s=96&d=mm&r=g","caption":"Gia s\u01b0 Qu\u1ed1c t\u1ebf"},"url":"https:\/\/giasuquocte.edu.vn\/en\/author\/gsqt_ad\/"}]}},"_links":{"self":[{"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/posts\/3164","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/comments?post=3164"}],"version-history":[{"count":0,"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/posts\/3164\/revisions"}],"wp:attachment":[{"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/media?parent=3164"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/categories?post=3164"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/giasuquocte.edu.vn\/en\/wp-json\/wp\/v2\/tags?post=3164"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}